Question

1000 N force is required to lift a hook and 10000 N force to lift a load slowly. Find power required to lift hook with load with speed v=0.5m/s.​

Answer 1

Answer:

Power = Force × velocity

Force = 10000 + 1000 = 11000 N

Velocity = 0.5 m/s

Power = 11000 × 0.5 = 5500 W

The answer is 5500W

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