Question

1000g aqueous solution of CaCO3 contains 10g of calcium carbonate concentration of the solution is

Answer 1

Molarity equals to no. Of moles present in unit volume of the solution
Then,M={10/100}×1000/1000
=o.1 molar

Answer 2

Answer: Molality of solution is 0.10.

Explanation:

Molality is defined as the number of moles of solute dissolved per kg of the solvent.

$Molality=\frac{\text{given mass of compound}}{\text{molar mass of compound}\times \text{weight of solvent in kg}}=\frac{\text{moles of compound}}{\text{weight of solution is kg}}$

given mass of solute $(CaCO_3)$= 10 g

Molar mass of solute $(CaCO_3)$= 100 g

Weight of solvent (water)=weight of solution- weight of solute=1000g-10g=990 g=0.99kg

$Molality=\frac{10g}{100g\times 0.99kg}=0.10m$