Question

100g ice at 0°c is mixed with 10g steam at 100°c find the final temp and composition.

Kindly solve the above question

Answer 1

Answer: The final temperature would be 67.2°C.

Answer 2

The final temperature is 67.2°C and 110 gm of water is present .

Let , final temperature of system be t .

Now , heat release by stream ice at 100°C to convert in ice is :$H_1=mL=10\times 540=5400\ cal$

Heat release to reach temperature t is :

$H_2=mS\Delta T\\H_2=10\times 1 \times ( 100 - t)\\H_2=10(100-t)$

Now , heat required by ice to convert ice at 0°C to water is :

$H_3=mL=100\times 80=8000 \ cal$

Heat required by water to reach temp t is :

$H_4=100\times 1\times ( t-0)$

Now , $H_1+H_2 = H_3 +H_4$

Putting all values , we get :

$t=67.2^{\circ}C$ .

Hence , this is the required solution .

Learn More :

Thermodynamics

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