100g of 104.5% oleum is diluted with 94.5g h2o. The morality of h2so4 in the resultant solution is
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Answered by
3
We first write the equation for the reaction :
H₂S₂O₇ + H₂O —> 2 H₂SO₄
The mole ratio is 1 : 2
Moles of Oleum diluted will be :
100 / 178 = 0.5618 moles
The moles of sulphuric acid produced is :
0.5618 × 2 =1.1236 moles.
Volume of water is:
(94.5g / 1g) × 1 cm³ = 94.5 cm³
1.1236 are in 94.5 cm³
Moles in 1000 cm³ will be
(1000 / 94.5) × 1.1236 = 11.89 M
H₂S₂O₇ + H₂O —> 2 H₂SO₄
The mole ratio is 1 : 2
Moles of Oleum diluted will be :
100 / 178 = 0.5618 moles
The moles of sulphuric acid produced is :
0.5618 × 2 =1.1236 moles.
Volume of water is:
(94.5g / 1g) × 1 cm³ = 94.5 cm³
1.1236 are in 94.5 cm³
Moles in 1000 cm³ will be
(1000 / 94.5) × 1.1236 = 11.89 M
Answered by
17
Explanation:
Ag3A = 3Ag + A
3 moles of Ag combine with 3 moles of A
Mass of Ag = 0.37
Mass of A = 607 - 0.37 = 606.63
Moles of Ag = 0.37/108 = 0.003426
Moles of A = 0.003426/3 = 0.001142
Molar mass of A = 606.63/0.001142 = 531211
A tribasic acid has 3 atom of H
Molar mass of the acid = 3 + 531211 = 531214 g/mol
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