100g of water at 60° C is added to 180 g of water at 95°C. The resultant temperature of the mixture is ??
Answers
Answered by
0
Answer:
Heat lost by the hot water=Heat gained by the cold water.
m
1
cΔT
1
=m
2
cΔT
2
20(60−T)=60(T−20)
60−T=3T−60
4T=120
T=30
o
C
Answered by
1
Answer:
The final temperature of water
is equal to 82.5°
this is your answer !
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