Question

100ml of propane gas undergoes combustions with 100ml of oxygen the total volume of the reaction mixture after the combustion ( All the measurements are taken at STP)

Answer 1

380ml is volume of the resultant mixture

Answer 2

Hey dear,

● Answer -
Total reaction mixture after combustion = 220 ml

● Explaination -
# Given -
V(C3H8) = 100 ml
V(O2) = 100 ml

# Solution -
Combustion of propane is given by reaction -
C3H8 + 5O2 --> 3CO2 + 4H2O

Hence, 1 mol C3H8 & 5 mol O2 on combustion give 3 mol CO2 & 4 mol H2O.
∴ 1 L C3H8, 5 L O2 => 3 L CO2, 4 L H2O
∴ 20 ml C3H8, 100 ml O2 => 60 ml CO2, 80 ml H2O

Total reaction mixture after combustion -
= Reaction products + Unreacted reactants
= 60 ml (CO2) + 80 ml (H2O) + 80 ml (C3H8)
= 220 ml

Hope this helped you...