Computer Science, asked by barnavk, 11 months ago

100points question.... answer if u can... it's a challenge​

Attachments:

Answers

Answered by anishasa
1

x+=y --> x=x+y

x+=y = 30 value of x is 30

y - =z --> y=y-z

y - =z = 5 value of y is 5

z+=x --> z=z+x

z+=x = 5+30 value of z is 35

++x --> Preincrement operator Here,The prefix increment operator immediately increases or decreases the current value of the variable. This value is then used in the expression.

The value of x is 31

y-- --> Postfix decrement operator In Post-decrement first value of variable is used in the expression and then decrement the value of variable.

The value of y is 4

z++ --> Preincrement operator Here,The prefix increment operator immediately increases or decreases the current value of the variable. This value is then used in the expression.

The value of z is 36

Answered by Abhis506
0

x+=y --> x=x+y

x+=y = 30 value of x is 30

y - =z --> y=y-z

y - =z = 5 value of y is 5

z+=x --> z=z+x

z+=x = 5+30 value of z is 35

++x --> Preincrement operator Here,The prefix increment operator immediately increases or decreases the current value of the variable. This value is then used in the expression.

The value of x is 31

y-- --> Postfix decrement operator In Post-decrement first value of variable is used in the expression and then decrement the value of variable.

The value of y is 4

z++ --> Preincrement operator Here,The prefix increment operator immediately increases or decreases the current value of the variable. This value is then used in the expression.

The value of z is 36

[

Similar questions