Physics, asked by sayalikurhadkar8256, 1 year ago

In a house 4 tube light of 50 watts each and three fans of 100watts each for 10 hours per day are used A water pump of 1 Horse power run for everyday Find out the consumption of electric energy in kwh per month ( 30 days)

Answers

Answered by spiky20
3
Hope this helps you
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Answered by sarasaifi845
0

Answer:

Power of tube light =200W

Power of fans =300W

Power of tube light +Power of fans =200+300

= 500W

For 10 house

500 × 10 = 5000W

Power of pump = 746W

Total power = 5000 + 746

= 5746W

Energy consumed = Total power × total time /1000

= 5746 ×30/1000

= 172.38 kilowatt -hour or unit

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