Question

1022 molecutes of co, is taken out from a Sample of 440 gram of CO2 find mass of sample .
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Answer 1

Answer:

Removed molecule =10

20

CO

2

=440 mg=0.44g

Molecular weight of CO

2

=12+32=44

Moles of CO

2

=

44

0.44

=0.01

Number of molecule = 0.01×6.023×10

23

= 6.023×10

21

Remaining molecule = initial − removed molecule

= 6.023×10

21

−0.1×10

21

= 5.923×10

21

Atom remaining = 3× remaining molecule

= 3×5.923×10

21

=1.77×10

21

Explanation:

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