Question

103-[144÷(12×12)+5+12÷6-2+10] solve it fast

Answer 1

Given: The term 103-[144÷(12×12)+5+12÷6-2+10]

To find: The value of the given expression.

Solution:

• Now we have given the term as  103-[144÷(12×12)+5+12÷6-2+10]

• Now we know the rule:

          BODMAS = Bracket of division multiplication addition and subtraction.

• So applying this, we get:

          103 - ( 144 / (12 x 12) + 5 + 12/6 - 2 + 10 )

• First doing all multiplications in brackets, we get:

          103 - ( 144 / 144 + 5 + 12/6 - 2 + 10 )

• Now dividing all the terms, we get:

           103 - ( 1 + 5 + 2 - 2 + 10 )

• Solving further, we get:

          103 - ( 6 + 10 )

          103 - 16

          87

Answer:

               So the value of the given term is 87.