105 into 95 using identity
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Answered by
18
105 × 100,
(100+5)×(100-5),
using identity
(a+b)(a-b)=a²-b², we have
(100)²-(5)²,
10000-25,
9975
(100+5)×(100-5),
using identity
(a+b)(a-b)=a²-b², we have
(100)²-(5)²,
10000-25,
9975
romanticgirlsexy:
its 9975
wrong
You corrected it now, and now its right
Answered by
2
100 square-5 square
10000-25
9975
10000-25
9975
hi
reply
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