Question

105²?
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Answer 1

(105)^2

(100+5)^2

(100)^2+2×5×100+(5)^2

10000+1000+25

11025 Answer

HOPE IT HELPS YOU

Answer 2

QUESTION

$105 {}^{2}$

SOLVING:

$105 {}^{2} = 105 \times 105 = (100 + 5)(100 + 5) = (100 + 5) { }^{2} \\ \\ Of \: the \: form : \\ (x + y) {}^{2} = x {}^{2} + 2xy + y {}^{2} \\ \\ = (100) {}^{2} + (5) {}^{2} + 2(100)(5) \\ \\ = 10000 + 25 + 1000 = 11025$

AS THE NUMBER IS ABOVE 100^2:

Step 1:We consider the number and add the unit's digit of the number.=>105+5=110

Step 2: Squaring the unit digit number=>(5)^2=25

Combining the numbers obtained in steps 1 and 2.

We get 11025

I have forgotten the second one.