Question

10g of ALCL3 number of ions in compound

Answer 1

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Answer 2

Answer:

Explanation:

mass = 10 g

molar mass of AlCl₃ = 27 + 35.5 × 3

                              = 27 + 106.5

                              =133.5 g

(∵ molar mass of aluminium = 27u , molar mass of chlorine = 35.5u)

moles = mass / molar mass

         =10/133.5

         = 0.07 mol

no of ions= moles × Na ( avogadro's no. = 6.02 × 10²³)

                         = 0.07  × 6.02 × 10²³

                         = 4.2 × 10²²