10g of ammonia find no.of moles and partical
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hey frnd.....
molar mass of ammonia (NH3) = 14+(1×3) = 14+3 = 17 g/mol
1) no of moles = given mass / molar mass
= 10/17
= 0.588 moles
2) no of particles in 1 moles of NH3 = 6.022×10^23
so....no of particles in 0.588 moles = 0.588 × 6.022×10^23
= 3.54 × 10^23
HOPE THIS HELP YOU ☺☺❤❤❤
molar mass of ammonia (NH3) = 14+(1×3) = 14+3 = 17 g/mol
1) no of moles = given mass / molar mass
= 10/17
= 0.588 moles
2) no of particles in 1 moles of NH3 = 6.022×10^23
so....no of particles in 0.588 moles = 0.588 × 6.022×10^23
= 3.54 × 10^23
HOPE THIS HELP YOU ☺☺❤❤❤
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