10g of hydrogen and 64g of oxygen are filled in a steel vessel and exploded . Volume of gaseous product after reaction?
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10g H2 = 5 moles H2
64g O2 = 2 moles O2
H2 + 1/2 O2 = H2O
Hence 4 moles H20 produce and 1 mole H2 will be left.
Total 5 moles gases left
Volume = 5 x 22.4L = 112L
64g O2 = 2 moles O2
H2 + 1/2 O2 = H2O
Hence 4 moles H20 produce and 1 mole H2 will be left.
Total 5 moles gases left
Volume = 5 x 22.4L = 112L
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