Question

10g of ice at 0 degrees and 10g of water at 10 degrees are mixed. What will be the final temperature?

Answer 1

Heya Mate !!!

Here's Your Answer ⏬

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• The 10 g of water can give up 1 cal/g/°C x 10 °C x 10g = 100 cal, which would cool the water to 0 °C.

=] To melt ice requires 79.72 cal/g.

So 100 cal / 79.72 cal/g = 1.25 g of ice would melt.

=> The end result would be: -

• 11.25 g of water at 0 °C.

And 

• 8.75 g of ice at 0 °C

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^_^ Hope It Helps ^_^

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