Question

10g of steam at 100degree C are condensed in 1000g of water at 30degree C. Find the final temperature......​

Answer 1

Answer:

Let M be the mass of steam condensed.

Amount of heat lost by the steam due to latent heat of condensation and due to cooling to 80

∘

C

=M×540+m(100−80)

Amount of heat absorbed by the water and calorimeter system=1100×1×(80−15)+20×1×(80−15)

From conservation of heat energy,

=M×540+M(100−80) =1100×1×(80−15)+20×1×(80−15)

⟹M=130g=0.130kg

pls mark me as the brainlest and pls subscribe my channel Nishka Shah which has 16 subscribers and is a new channel

Answer 2

Answer:

my old I'd..............