Question

10gm., 30gm and 60gm are at 20cm, 40cm
and 80cm on light metre scale. The position
of the centre of mass of the system is​

Answer 1

Answer:

100gm and 140 total is 250

Step-by-step explanation:

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Answer 2

$\huge{\fcolorbox{pink}{indigo}{\fcolorbox{lime}{purple}{\fcolorbox{red}{gray}{\green{Good\: Night}}}}}$

$\bf\pink{For\: Center\:Of\:Mass,\:we\: know \:that}$

$\blue\bigstar\:\bf\green{X_{cm}\:=\:\dfrac{M_1\:X_1\:+\:M_2\:X_2\:+\:M_3\:X_3}{M_1\:+\:M_2\:+\:M_3}\:}$

$\Large\bf\orange{Where,}$

• $\bf\red{M_1}$ = 10 gm.

• $\bf\green{M_2}$ = 30 gm.

• $\bf\red{M_3}$ = 60 gm.

• $\bf\green{X_1}$ = 20 cm.

• $\bf\red{X_2}$ = 40 cm.

• $\bf\green{M_1}$ = 80 cm.

$\longmapsto\:\rm{X_{cm}\:=\:\dfrac{10\times{20}\:+\:30\times{40}\:+\:60\times{80}}{10\:+\:30\:+\:60}\:}$

$\longmapsto\:\rm{X_{cm}\:=\:\dfrac{200\:+\:1200\:+\:4800}{1000}\:}$

$\longmapsto\:\rm{X_{cm}\:=\:\dfrac{6200}{1000}\:}$

$\red\longmapsto\:\rm\pink{X_{cm}\:=\:62\:cm}$

$\bold\therefore$ The position of the centre of mass of the system is 62 cm from zero cm towards the metre scale.