10gm H2 & 64gm O2 are exploded in a steel vessel.If the product formed at S.T.P is gaseous total volume of mixture after reaction is-
a)1*22.4lit
b)2*22.4lit
c)3*22.4lit
d)4*22.4lit
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it is b buddy. coz here there is no limiting reactant but hydrogen is in excess so we just remove l extra mole of h2 from 5 moles h2 ......
then the reaction is likeaway .. 4moles of h2 combine with 2 moles of o2 to form 2 moles of water ... since water is now 2 moles ... the vol. is 2× 22.4lit
then the reaction is likeaway .. 4moles of h2 combine with 2 moles of o2 to form 2 moles of water ... since water is now 2 moles ... the vol. is 2× 22.4lit
purohitsumitm:
can u explain it in the form of a sum?
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