10gm of water is heated through 50c° . how much heat is required ?
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Answer:
Heat required to melt ice at −20
o
C into water at 0
o
C is
10×0.5×[0−(−20)]+10×80
=100+800=900cal
Heat released by water at 10
o
C =10×1(10−0)
=100cal
Because required heat is much more than that of released heat. So, final temperature of the mixture is 0%
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