10mL of a solution of NaOH is found to be completely neutralised by 8mL of a given solution of HCL. If we take 20mL of the same solution of NaOH, the amount of HCL solution required to neutralise it will be-
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If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be. 10 mL of NaOH will require HCl = 8 mL and 20 mL of NaOH will require HCl= 16 mL. Therefore, (d) is the correct answe
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Solution:
8 mL of HCl solution is required to neutralise 10 mL of NaOH.
So, as usual to neutralise 20 mL of same solution i.e. of NaOH. We would need 16 mL of same solution of HCl.
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