10ml of CO is mixed with 25ml air having 20% O2 by volume.What would be the final volume if none of CO and O2 is left after the reaction?
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2(CO) + O2 - - - - - - > 2(CO2)
20% of 25 mL = 5 mL (oxygen in air)
2 moles of CO completely reacts with 1 mole of O2 to give 2 moles of CO2
1 mole of a gas = 22400 mL
So 22400 mL CO will react with 11200 mL O2 to give 22400 mL of CO2
Therefore 10 mL of CO will react with 5 mL O2 to give 10 mL of CO2
Now as there is no CO and O2 left after reaction, therefore, final volume will be 10mL
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