Question

10ml of HNO3 is added to 290 ml of water.find the concentration of solution?
please write full process​

Answer 1

Given:

• $\sf 10ml$ of $\sf HNO _{3}$ is added to $\sf 290 ml$ of water. Find the concentration of solution?

To find:

• The concentration of Solution

Solution:

• First we have to find the the volume of solution.
• So let's calculate,

$\sf \: Volume \: of \: solution = 10ml + 290 ml$

$\sf \: Volume \: of \: solution = 300ml$

Therefore,

• Concentration of Solution

$\begin{gathered} : \implies\sf{ \frac{10}{3{ \cancel{00}}}\times1{\cancel{00}}} \end{gathered} \\ \\\begin{gathered} : \implies\sf{ \frac{10}{3}} \\ \end{gathered} \\ \\ : \implies \underline{\boxed{\frak{ 3.33\%}}} \pink\bigstar$

$\therefore\begin{gathered}\underline{ \sf{Hence, \: the \: required \: concentration \: of \: solution \: is {\textsf{ \textbf{3.33\%} .}}}} \end{gathered}$

тнαηк үσυ

||TheUnknownStar||

Answer 2

To find the concentration of sol. first we have to find the the volume of solution.So let's calculate,

V of sol. = 10 + 290

V of sol. = 300ml

Therefore, Concentration of sol.

$\begin{gathered} \sf{ = \frac{10}{3{ \cancel{00}}}\times1{\cancel{00}}} \\ \end{gathered}$

$\begin{gathered} \sf{ = \frac{10}{3}} \\ \end{gathered}$

$\sf\frak\orange{ = 3.33\%}$

Hence, the required

concentration of solution is 3.33%