Question

10ml of HNO3 is added to 290 ml of water.find the concentration of solution? please write full process​

Answer 1

Answer :-

Concentration of the solution is 3.33 % .

Explanation :-

We have :-

→ Volume of HNO₃ = 10 mL

→ Volume of water = 290 mL

________________________________

Here, HNO₃ [nitric acid] is solute and water is solvent. Firstly, we have to calculate the total volume of the solution .

Volume of solution :-

= Volume of solute + Volume of solvent

= (10 + 290) mL

= 300 mL

Now, let's calculate the concentration of the solution . In this case it is volume by volume percentage concentration .

Concentration of solution :-

= Vol. of solute/Vol. of solution × 100

= 10/300 × 100

= 1000/300

= 10/3

= 3.33 %

Answer 2

To find the concentration of sol. first we have to find the the volume of solution.So let's calculate,

V of sol. = 10 + 290

V of sol. = 300ml

Therefore, Concentration of sol.

$\sf{ = \frac{10}{3{ \cancel{00}}}\times1{\cancel{00}}}$

$\sf{ = \frac{10}{3}}$

$\sf\frak\orange{ = 3.33\%}$

Hence, the required

concentration of solution is 3.33%