10ml of N/2 KOH , 30ml of N/10 NaOH , 75ml of N/5 Mg(OH)twice are mixed together the normality of solution is
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Normality=eq.of solute/volume in litre
total milli.equ.=(10×0.5)+(30×0.1)+(75×0.2)
=23
Total volume=10+30+75
=115 ml.
Normality=23/115
=0.2N
total milli.equ.=(10×0.5)+(30×0.1)+(75×0.2)
=23
Total volume=10+30+75
=115 ml.
Normality=23/115
=0.2N
HRITHIKmu007:
Thanks alot buddy
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