Math, asked by kishansinghdl2pdl9h5, 1 year ago

the perimeter of a rectangle is 30m i if its lenth exceeds its bredth by 3m then find it length

Answers

Answered by Aman1245
2
let the of the breadth of the rectangle be x then its length is x+3

A/q=2(x+x+3)=30m
=2x+2x+6=30
=4x=>30-6
=x=>24/4
x=>6

hence,length of rectangle=6+3=9m.

hope this helps ☺

Aman1245: mark brainliest plz
Answered by TooFree
5

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 \textbf {Hey there, here is the solution:}

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 \textbf {Let the breadth be x}

 \textbf {The length is x + 3}

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 \textbf {Given that the perimeter is 30m:}

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 \textbf {Perimeter = 2(Length + Breadth)}

 \textbf {30 = 2(x + 3 + x)}

 \textbf {30 = 2(2x + 3}

 \textbf {30 = 4x + 6}

 \textbf {4x = 24}

 \textbf {x = 6}

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 \textbf {Find the length and breadth:}

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 \textbf {Breadth = x = 6 m}

 \textbf {Length = x + 3= 6 + 3 = 9m}

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 \boxed {\textbf {Answer: Length = 9m and breadth = 6m}}

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 \textbf {Cheers @ Simmisai }

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