Question

10ml of N2 is reacted with 20ml of H2 to form NH3. The correct statements is/are
A)13.3ml NH3 formed
B)20ml of NH3 formed
C)3.4ml N2 left after reaction
D)16.7ml of mixture is left after completion of reaction

Answer 1

N2 + 3H2 -> 2NH3 is the balanced equation

1 vol requires 3 vol of H2 ... As per the question 10 ml requires 30 ml H2

So considering 20 ml H2 then only 10*2/3 = 6.67 ml can react and they combine to form

2*6.67 = 13.34ml NH3 with 3.33ml N2 left over

option is A and C (if approximated)

Answer 2

Answer:

10ml of $N_2$   is reacted with 20ml of  $H_2$  to form $NH_3$. The correct statements are

A)13.3ml $NH_3$ formed

C)3.4ml $N_2$  left after reaction

Explanation:

According to the given data the correct equation is,

$N_2 + H_2 \rightarrow NH_3$

Again the balanced form of the equation is,

$N_2 + 3H_2 \rightarrow 2NH_3$

Now, from the above equation it is clear that 1 volume of $N_2$ reacts with 3 volume of $H_2$ to produce 2 volume of $NH_3$.

Again, it id given in the question that the volume of

$N_2$  is 10ml,

$H_2$  is 20ml

As per the question 10 ml $N_2$  requires 30 ml $H_2$ .

So considering 20 ml $H_2$ then only $10\times \frac{2}{3} = 6.67$ ml can participate in the reaction and then they combine to form $2\times6.67 = 13.34$ ml  $NH_3$ having 3.33ml $N_2$  left over after the reaction.

Hence, the correct answer is option(a) 13.3ml $NH_3$ formed and option (c) 3.4ml $N_2$  left after reaction.

To know more about this answer, click on the link given below,

https://brainly.in/question/17418631

https://brainly.in/question/17132886

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