Question

10p−3=2(12+4p)−7?
solve for p

Answer 1

$\huge\boxed{\red{\bold{Answer}}}$

To find the value of P

According to question:-

$\sf 10p-3 = 2(12+4p)-7 \\ \sf\implies 10p-3=24+8p-7 \\ \sf\implies 10p-3=17+8p \\ \sf\implies 10-8p=17+3\\ \sf\implies2p=20\\ \sf\implies p=\frac{20}{2}\\ \sf\implies p=10$

The value of P is 10

$\huge\boxed{\red{\sf{Verification}}}$

Put the value of p in equation

10p-3=2(12+4p)-7

$\sf 10×10-3=24+8×10-7\\ \sf\implies 100-3=24+80-7\\ \sf\implies 97=104-7\\ \sf\implies 97=97$

$\huge\boxed{\red{p=10}}$

Answer 2

Question :----

• Solve for p ,, 10p -3 = 2(12+4p) -7

remember that, anyting goes from LHS to RHS or vice - versa , their sign will change,

using this ,

solution :-----

10p - 3 = 2(12+4p) - 7

→ 10p - 3 = 24 + 8p - 7

→ 10p - 3 = 17 + 8p

taking p values same side now,

→ 10p - 8p = 17 + 3

→ 2p = 20

→ p = 20/2

→ p = 10 ...

Lets verify our Answer now,

putting p = 10 ,

10×10 - 3 = 2(12+4×10) - 7

→ 100-3 = 2(12+40)-7

→ 97 = 2×52 - 7

→ 97 = 104 -7

→ 97 = 97

so, value of P = 10 (Ans)

(Hope it helps you)