10picture of saroja's birthday have to be framed. each picture is of length 10cm, breadth 8cm. (i) find the length of a wooden frame required to frame the pictures. (ii) area of the glass required to cover the front of the picture
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LENGTH OF WOODEN FRAME :-
perimeter of the rectangular picture = 2(10+8) = 2(18) = 36 cm
length of wooden frame required for 1 picture = 36 cm
length of wooden frame required for 10 pictures = 36 x 10 = 360 cm
___________________________
AREA OF GLASS :-
area = 10 x 8 = 80 cm^2
area of 1 picture = 80cm^2
area of 10 pictures = 80x10 = 800cm^2
perimeter of the rectangular picture = 2(10+8) = 2(18) = 36 cm
length of wooden frame required for 1 picture = 36 cm
length of wooden frame required for 10 pictures = 36 x 10 = 360 cm
___________________________
AREA OF GLASS :-
area = 10 x 8 = 80 cm^2
area of 1 picture = 80cm^2
area of 10 pictures = 80x10 = 800cm^2
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