Question

10th class problem Helpp guysss Stucked in this

Answer 1

Answer:

Step-by-step explanation:

i will take theta as x

as we know cos²x +sin²x=1

so cos²x=1-sin²x

therefore cos²x=1-(√3/2)²

cos²x=1-3/4= 1/4

and cotx=1/tanx

therefore cotx= 1/√3

Now put the values

1/4 + √3/2*1/√3

1/4+1/2

3/4

Answer 2

Answer:

Step-by-step explanation:

sin²θ =3/4

Therefore using the Identity

sin²A + cos²A=1

We have 1-sin²A=cos²A

Therefore 1-3/4= cos²A=¼

cotθ=1/tanθ

=1/√3

Therefore sinAcotA is√3/2×1/√3=1/2

Therefore answer is 1/2+1/4=3/4

Plz Mark brainliest