10th first angle name
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<AOD=<COB(Vert. oppo.angles)
<AOD=36°
Since,AB is a straight line
so,<AOC+BOC=180°(linear pair)
>AOC+36°=180°
>AOC=180°-36°
=144°
So,<DOB=144°(vert.oppo.angles.
<AOD=36°
Since,AB is a straight line
so,<AOC+BOC=180°(linear pair)
>AOC+36°=180°
>AOC=180°-36°
=144°
So,<DOB=144°(vert.oppo.angles.
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