Math, asked by pdixit473, 11 months ago

10th question to be answered

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Answers

Answered by ITzBrainlyGuy
1

Step-by-step explanation:

(x^2+1/x^2)-3(x-1/x)-2=0

(x^4+1/x^2)-3(x^2-1/x)-2=0

(x^2+1)-3(x-1)-2=0

(x^2+1)-(3x-3)-2=0

(x^2+1)-3x+3=0

(x^2+1)+3=3x

(x^2+3)+(1+3)=3x

(x^2+3)+(4)=3x

(x^2+3)+(4)/3=x

x^2+4=x

0=x^2+4-x

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