10th question to be answered
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Step-by-step explanation:
(x^2+1/x^2)-3(x-1/x)-2=0
(x^4+1/x^2)-3(x^2-1/x)-2=0
(x^2+1)-3(x-1)-2=0
(x^2+1)-(3x-3)-2=0
(x^2+1)-3x+3=0
(x^2+1)+3=3x
(x^2+3)+(1+3)=3x
(x^2+3)+(4)=3x
(x^2+3)+(4)/3=x
x^2+4=x
0=x^2+4-x
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