10th term of an arithmetic sequence is 24 and it's 14th term is 36
What is it's common difference?
What is the first term of this sequence?
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Answer:
we have given that a10th = 24 and a14th = 36 then
we know that
an = a+(n-1)d
then a10 = a + (10-1)d
24 = a + 9d.....1st equation
and
a14th = a+ (14-1)d
36 = a+13d....2nd equation
from equation 2nd and 1st
a+13d = 36
a+9d = 24
- - -
__________
4d = 12
d = 3
put the value of d in equation 1st
24 = a + 9 (3)
24 = a + 27
24 - 27 = a
a = -3
hence, common difference(d )= 3 and first sequence (a) = -3
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