10th term of an arithmetic sequence is 82 If its common difference is 8, find the position of the term 250 in sequence?
Answers
Answered by
42
a+9d=82
d=8.
so, a+9(8)=82
a+72=82
a=10
d=8
an=a+(n-1)d
250=10+(n-1)8
250=10+8n-8
250=2+8n
8n=250-2
8n=248
n=248/8
n=31
HOPE YOU LIKE IT!!!
d=8.
so, a+9(8)=82
a+72=82
a=10
d=8
an=a+(n-1)d
250=10+(n-1)8
250=10+8n-8
250=2+8n
8n=250-2
8n=248
n=248/8
n=31
HOPE YOU LIKE IT!!!
Answered by
3
Step-by-step explanation:
a+ 9d = 82
d = 8
So, a+9(8) = 82
a+ 72 = 82
a = 10
d = 8
an = a+( n-1) d
250 =10+8n-8
250= 2+8n
8n = 248
n = 248/8
n = 31
Hope you like this...
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