Question

10th term of ap is 64 if the common is 7 find the position of the term 400 in the sequence?​

Answer 1

GIVEN :-

10th term of an A.P = 64

Common difference = 7

TO FIND :-

400th term of an A.P.

USED FORMULA :-

$nth \: term \: = \: a + (n - 1)d$

Where; a = First term of A.P

n = nth term of A.P

d = Common Difference

PROCESS :-

10th term of an A.P = 64

a = we have to find,

n = 10

d = 7

nth term = 64

$64 = a + (10 - 1)7$

$64 = a +(9)7$

$64 = a + 63$

$a = 1$

_____________________________________________________

400th term of A.P = ?

a = 1

n = 400

d = 7

nth term = ?

$= 1 + (400 - 1)7$

$= 1 + (399)7$

$= 1 + 2793$

$= 2794$

ANSWER :-

400th term of an A.P = 2794

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