10th term of the sequence √3,√12,√27 ...is √3n2. find the value of n\2
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sorry friend I don't know the answer of this question
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Answer:
10√3 or √300
Step-by-step explanation:
a=√3
a2=√12 =√4×3=2√3
a3=√27=√9×3=3√3
therefore it is an ap with a=√3 and d=√3
then
a n= a+(n-1)d
a10=√3+(10-1)√3
=√3+9√3
=10√3
=√300
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