10x + 3y = 75
6x - 5y = 11
( Substitution method )
VijayaLaxmiMehra1:
Venus International School
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Hey!!
10x + 3y = 75 ----------- ( 1 )
6x - 5y = 11 -------------- ( 2 )
From eq'n ( 1 )
10x + 3y = 75
=> 3y = 75 - 10x
=> y = ( 75 - 10x / 3 ) --------- ( 3 )
Substitute eq'n ( 3 ) in eq'n ( 2 )
6x - 5y = 11
=> 6x - 5 ( 75 - 10x / 3 ) = 11
=> 18x - 375 + 50x = 33
=> 68x = 33 + 375
=> 68x = 408
=> x = 408 / 68
=> x = 6
From eq'n ( 3 )
y = ( 75 - 10x / 3 )
=> y = 75 - 10 ( 6 ) / 3
=> y = 75 - 60 / 3
=> y = 15 / 3
=> y = 5
Therefore the value of x = 6 and y = 5
Hope it helps☺☺
10x + 3y = 75 ----------- ( 1 )
6x - 5y = 11 -------------- ( 2 )
From eq'n ( 1 )
10x + 3y = 75
=> 3y = 75 - 10x
=> y = ( 75 - 10x / 3 ) --------- ( 3 )
Substitute eq'n ( 3 ) in eq'n ( 2 )
6x - 5y = 11
=> 6x - 5 ( 75 - 10x / 3 ) = 11
=> 18x - 375 + 50x = 33
=> 68x = 33 + 375
=> 68x = 408
=> x = 408 / 68
=> x = 6
From eq'n ( 3 )
y = ( 75 - 10x / 3 )
=> y = 75 - 10 ( 6 ) / 3
=> y = 75 - 60 / 3
=> y = 15 / 3
=> y = 5
Therefore the value of x = 6 and y = 5
Hope it helps☺☺
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