∫10x
+![10^{x}[/tex[tex]\frac{10x[tex]x^{9}](https://tex.z-dn.net/?f=10%5E%7Bx%7D%5B%2Ftex%5Btex%5D%5Cfrac%7B10x%5Btex%5Dx%5E%7B9%7D "10^{x}[/tex[tex]\frac{10x[tex]x^{9}")
+![10^{x}[/tex log 10 }÷[tex]10^{x}](https://tex.z-dn.net/?f=10%5E%7Bx%7D%5B%2Ftex+log+10+%7D%C3%B7%5Btex%5D10%5E%7Bx%7D "10^{x}[/tex log 10 }÷[tex]10^{x}")
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Hello I didn't understand your question
Step-by-step explanation:
please clarify
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