Math, asked by sahistajawed, 1 year ago

10xy (14y2 + 43y - 21) ÷ 5x(7y - 3)


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Answers

Answered by RDEEP90
3

Let's factorise first,

14 × ( - 21 ) = - 294

By the L.C.M of 294 we get

294 = 2 × 7 × 3 × 7

Now, we have to find whose sum can be + 43.

( Remember that one should be - ve sunce porduct was - 294. )

= 49 - 6 = 43

Hence,

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