10xy (14y2 + 43y - 21) ÷ 5x(7y - 3)
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Let's factorise first,
14 × ( - 21 ) = - 294
By the L.C.M of 294 we get
294 = 2 × 7 × 3 × 7
Now, we have to find whose sum can be + 43.
( Remember that one should be - ve sunce porduct was - 294. )
= 49 - 6 = 43
Hence,
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