Question

10y-69+32=2y+25. plesse ​

Answer 1

Answer:

10y-69+32=2y+25

10y-2y=25-32+69

8y=-7+69

8y=62

y=62/8

y=7.75

Hope it helps you.

Answer 2

Answer:

The required value of $y$ is $7.75$.

Step-by-step explanation:

Given : The expression is $10y-69+32=2y+25$

To find : The value of $y$.

Solution :

• The given expression is $10y-69+32=2y+25$
• We have to find the value of $y$.
• To find the value of $y$, use transposing method.
• Now, the expression is,

         $10y-69+32=2y+25$

• Transpose terms with variable at one side and constant terms at other side, we get

                ∴ $10y-2y=25+69-32$

                        ∴ $8y=62$

                          ∴ $y=\frac{62}{8}$

                           ∴ $y=7.75$

• ∴ The required value of $y$ is $7.75$.