Q7 The diagonals of a rhombus are 16 cm and 12 cm, find a) Its area b) Its length of the side e) Its perimeter
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a)Area=1/2×d1×d2
=1/2×16×12
=1/2×192
=96 cm2
c)Diagonal of rhombus = 12cm and 16cm
half of diagonal = 6cm and 8cm
by using Pythagoras theorem
at the point o where diangonals are meet at that point there are angle formed 90°
so,
a (side) of rhombus = √p² + b²
a = √6² + 8² = √36+64 =√ 100 = 10cm
now , as we know that Perimeter of rhombus
= 4a = 4×10 = 40cm
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