Question

10years ago a man age was 6 times the age of his son 12 years later the age of the son will be 27 years what is the present age of father

Answer 1

Let the present age of father be x

and age of his son be y

10 years ago

Age of father = x-10

Age of son = y-10

According to the question

x-10=6(y-10)

x-10=6y-60

x-6y=-60+10

x-6y=-50 ......(1)

After 12 years

Age of son = y+12

According to the question

y+12 =27

y=27-12

y=15

Now substitute the value of y=15 in equation (1), we get

x-6(15)=-50

x-90=-50

x=-50+90

x=40

Therefore, the present age of father is 40 years.