Question

10years ago age of c mother was 4times the age of c after 10years she would be double the age of c find the present age of c mother​

Answer 1

Answer:

let the age of c 10 years ago be X

then, age of c mother=4 X

present age of c=X+10

present age of c mother=4x+10

after 10 year of present age c= X +10+10=X+20

c mother=4x+10+10=4x+20

a/q

4x+20=2(X+20)

4x+20=2x+40

4x-2x=40-20

2x=20

X=20/2=10

so the present age of c mother=4x+10=4*10+10

=40+10=50

Answer 2

Answer:

C age=20 and C's mother age=50

Solution:-

Let the age of c be x

And c's mother age be 4x

10 years ago

C age be x+10

C's mother age=4x+10

Now after 10 years

C age=x+10+10

=x+20

C's mother age=4x+10+10

=4x+20

Now according to the question

4x+20=2(x+20)

4x+20=2x+40

4x-2x=40-20

2x=20

x=10

----------

C age=x+10

=10+10

=20

C's mother age=4x+10

=4×10+10

=50