Math, asked by mjanghu504, 28 days ago

11/10)^3-(3/5)^3-(1/2)^3​ which identity will be used​

Answers

Answered by sakshi101106
0

Answer:

99/10

Step-by-step explanation

identity = a^3 + b^3 + c^3 - 3abc = ( a + b + c ) ( a^2 + b^2 + c^2 - ab - bc - ac)

if a + b + c = 0

then a^3 + b^3 + c^3 = 3abc

here a = 11/10 , b = -3/5 , c = -1/2

a + b + c = 11/10 + ( -3/5 ) + ( -1/2 )                                                  ( L.C.M = 10 )

              = 11/10 - 3/5 - 1/2

              = 11 - 6 - 5 / 10

              = 0/10

              = 0

a^3 + b^3 + c^3 = 3abc

( 11/10 )^3 + ( -3/5 )^3 + ( -1/2 )^3 = 3 × 11/10 × ( -3/5 ) × ( -1/2 )

                                                   = 33/10 × 3/10

                                                   = 99/10

Similar questions