11/10)^3-(3/5)^3-(1/2)^3 which identity will be used
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Answer:
99/10
Step-by-step explanation
identity = a^3 + b^3 + c^3 - 3abc = ( a + b + c ) ( a^2 + b^2 + c^2 - ab - bc - ac)
if a + b + c = 0
then a^3 + b^3 + c^3 = 3abc
here a = 11/10 , b = -3/5 , c = -1/2
a + b + c = 11/10 + ( -3/5 ) + ( -1/2 ) ( L.C.M = 10 )
= 11/10 - 3/5 - 1/2
= 11 - 6 - 5 / 10
= 0/10
= 0
a^3 + b^3 + c^3 = 3abc
( 11/10 )^3 + ( -3/5 )^3 + ( -1/2 )^3 = 3 × 11/10 × ( -3/5 ) × ( -1/2 )
= 33/10 × 3/10
= 99/10
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