Question

if the base of the triangle is
$( \frac{5}{3} ) {}^{3} \: m \: and \: its \: altitude \: is \: ( \frac{9}{2} ) {} {}^{2 \: m \: find \: the \: area \: of \: triangle}$
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Answer 1

Step-by-step explanation:

$area = \frac{1}{2} \times { (\frac{5}{3}) }^{3} \times { (\frac{9}{2} )}^{2} \\ = \frac{5 \times 5 \times 5 \times 9 \times 9}{3 \times 3 \times 3 \times 2 \times 2} \\ = \frac{375}{4} \\ = 93.75 \: {cm}^{2}$