Math, asked by kharateyogesh007, 3 months ago

11,111.111111111 =(100+r)×(100+r) then what is the value of r ??​

Answers

Answered by baljindersinghg12197
2

Answer:

11,111.111111111=(100+r)²

11,111.111111111=100²+2×100+r² {(a+b)² = a²+2ab+b²}

11,111.111111111=10000+200+r²

11,111.111111111=10200+r²

11,111.111111111-10200=r²

911.111111=r²

√911.111111=r

30.1846171=r (ANSWER)

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kharateyogesh007: 100²+2×100×r+r²
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