11
17 An escalator in an underground station has 25 people standing on it and is moving with a speed
of 43 ms. The average mass of a person is 78 kg and the angle of the escalator to the
honzontal is 40
What is the minimum power required to lift these people?
P=FV
A
5.4 kW
B
6.4 KW
C 53 kW
63 kW
Answers
Answered by
1
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Explanation:
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Answered by
5
Answer:
C will be the answer
Explanation:
force= mgsin40
25×78×9.81×sin40 = 12296.2
now apply formula of power
power = F×V
12296.2×4.3 =52873.68
which will be approximately 53000 so 53kW will be the answer
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