Question

11.2 litre O2 at STP and 8 gram calcium react together volume of O2 left​

Answer 1

Answer:

8.96 litre

Explanation:

11.2 O2 st STP is 0.5 moles. The reaction between Ca and O2 is:

2Ca + O2 → 2CaO

So 2 moles of Ca reacts with 1 mole of O2. 8 grams of Ca is 0.2 moles.

Ca is limiting reagent so 0.2 moles of Ca reacts with 0.1 moles of O2.

0.5 - 0.1 = 0.4 moles of O2 left

0.4 moles of O2 is 8.96 $dm^{3}$ or litre