Question

11) 200 ml of 0.05 M H2SO4 is diluted by adding 1L water. What is the molarity of the diluted solution? (Ans: 0.0083 moles/L)

Answer 1

initial moles

$of H_{2}SO_{4}=x$

x can be calculated as

$we\:know\:that \:\\molarity=\frac{moles}{volume in litre} \\moles =M\times volume \\x=0.05\times 200/1000L\\x=0.01moles$

new volume of solvent =initial +added

V'=0.2l=1l=1.2l

New molarity M' can be calculated as

$M'=moles/volume\\M'=\frac{0.01}{1.2} \\M'=0.0083333 M$

Answer 2

see the attachment..


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