Question

11. 2x(y² + 1) dx + (x⁴ + 1) dy = 0. find general solution.​

Answer 1

Answer:

Given differential equation is

(2x−y+1)dx+(2y−x+1)dy=0

⇒2x dx+2y dy−(y dx+x dy)+dx+dy=0

⇒(2x dx+2y dy)−d(xy)+dx+dy=0

On integrating both sides, we get

x

2

+y

2

−xy+x+y=c

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